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Venice (in Erie County, OH) Populated Place Profile

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Venice: Basic Facts & Information

Venice is a populated place LOCATED WITHIN the City of Sandusky. In turn, the City of Sandusky is located within Erie County.

Venice is located at latitude 41.446 and longitude -82.77.

Since Venice is located within the City of Sandusky, all of the census and demographic data for residents of Venice are included as part of the information reported for City of Sandusky in the "Profile" tab above.

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Nearby Cities, Towns & Census Designated Places

Bay View, OH (3.4 miles WNW)
Sandusky, OH (3.4 miles E)
Castalia, OH (3.6 miles SSW)
Crystal Rock, OH (3.9 miles W)
Bloomingville, OH (6.7 miles SSE)

Whites Landing, OH (6.8 miles W)
Whites Landing, OH (6.8 miles W)
Lakeside, OH (6.8 miles N)
Marblehead, OH (6.8 miles NNE)
Vickery, OH (9.6 miles WSW)

Nearby Neighborhoods, Subdivisions & Other Small Populated Places

Westview Estates, OH (< 0.1 mile)
Baywater Estates, OH (< 0.1 mile)
Lions Park, OH (1.4 miles E)
MacArthur Park, OH (2.7 miles ESE)
Holiday Estates, OH (3.4 miles ESE)

Danbury, OH (4.7 miles NW)
Ranch Wood, OH (4.9 miles ESE)
Southgate Acres, OH (4.9 miles ESE)
Lincolnshire, OH (4.9 miles ESE)
Weyers, OH (4.9 miles S)