Venice (in Erie County, OH) Populated Place Profile

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Venice is a populated place LOCATED WITHIN the City of Sandusky. In turn, the City of Sandusky is located within Erie County.

Venice is located at latitude 41.446 and longitude -82.77. The elevation of Venice is 581 feet above mean sea level.

Since Venice is located within the City of Sandusky, all of the census and demographic data for residents of Venice are included as part of the information reported for City of Sandusky in the "Data" tab above.

In similar fashion, ALL OF THE NAVIGATION TABS ABOVE ARE FOR THE City of Sandusky Community Profile.

Erie County: Cities & Towns | ZIP Codes | Schools | Features (airports, churches, hospitals, etc.)

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BIG Map | Driving Directions | Data Source - USGS GNIS FID: 1049272

BOUNDARY MAPS: City of Sandusky | Erie County

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Nearby Cities, Towns & Census Designated Places

Sandusky, OH (3.4 miles E)
Bay View, OH (3.4 miles WNW)
Castalia, OH (3.6 miles SSW)
Crystal Rock, OH (3.9 miles W)
Marblehead, OH (6.8 miles NNE)
Lakeside, OH (6.8 miles N)
Whites Landing, OH (6.8 miles W)
Whites Landing, OH (6.8 miles W)
Vickery, OH (9.6 miles WSW)
Port Clinton, OH (9.8 miles WNW)

Nearby Neighborhoods, Subdivisions & Other Small Populated Places

Baywater Estates, OH (< 0.1 mile)
Anchor Mobile Home Park, OH (< 0.1 mile)
Westview Estates, OH (< 0.1 mile)
Lions Park, OH (1.4 miles E)
Greenfield Village Mobile Home Park, OH (1.9 miles SE)
Hoopers Mobile Home Park, OH (1.9 miles E)
MacArthur Park, OH (2.7 miles ESE)
Holiday Estates, OH (3.4 miles ESE)
Danbury, OH (4.7 miles NW)
Southgate Acres, OH (4.9 miles ESE)