The Village of Jefferson had a population of 3,036 as of July 1, 2016.
The primary coordinate point for Jefferson is located at latitude 41.7384 and longitude -80.769 in Ashtabula County. The formal boundaries for the Village of Jefferson (see map below) encompass a land area of 2.52 sq. miles and a water area of 0 sq. miles. Ashtabula County is in the Eastern time zone (GMT -5). The elevation is 961 feet.
The Village of Jefferson (GNIS ID: 2398292) has a C1 Census Class Code which indicates an active incorporated place that does not serve as a county subdivision equivalent. It also has a Functional Status Code of "A" which identifies an active government providing primary general-purpose functions.
Beneath the boundary map are tables with Jefferson population, income and housing data, five-year growth projections and peer comparisons for key demographic data. The estimates are for July 1, 2016.
|Population in Households||2,956|
|Population in Familes||2,400|
|Population in Group Qrtrs||80|
|Average Household Size||2.31|
|Average Family Size||3|
|Total Housing Units||1,410 (100%)|
|Owner Occupied HU||853 (60.5%)|
|Renter Occupied HU||426 (30.2%)|
|Vacant Housing Units||130 ( 9.2%)|
|Median Home Value||$145,102|
|Average Home Value||$156,674|
|Median Household Income||$54,226|
|Average Household Income||$63,258|
|Per Capita Income||$26,654|
|(Compound Annual Growth Rates)|
|Median Household Income||2.09%|
|Per Capita Income||2.26%|
The table below compares Jefferson to the other 1,215 incorporated cities, towns and CDPs in Ohio by rank and percentile using July 1, 2016 data. The location Ranked # 1 has the highest value. A location that ranks higher than 75% of its peers would be in the 75th percentile of the peer group.
|Total Population||# 398||67th|
|Population Density1||# 628||48th|
|Diversity Index2||# 787||36th|
|Median Household Income||# 404||67th|
|Per Capita Income||# 363||70th|
Additional comparisons and rankings can be made with a VERY EASY TO USE Ohio Census Data Comparison Tool.