The Village of Jefferson had a population of 3,074 as of July 1, 2018.
The primary coordinate point for Jefferson is located at latitude 41.7384 and longitude -80.769 in Ashtabula County. The formal boundaries for the Village of Jefferson (see map below) encompass a land area of 2.52 sq. miles and a water area of 0 sq. miles. Ashtabula County is in the Eastern time zone (GMT -5). The elevation is 961 feet.
The Village of Jefferson (GNIS ID: 2398292) has a C1 Census Class Code which indicates an active incorporated place that does not serve as a county subdivision equivalent. It also has a Functional Status Code of "A" which identifies an active government providing primary general-purpose functions.
Beneath the boundary map are tables with Jefferson population, income and housing data, five-year growth projections and peer comparisons for key demographic data. The estimates are for July 1, 2018.
|Population in Households||2,994|
|Population in Familes||2,442|
|Population in Group Qrtrs||80|
|Median Household Income||$56,493|
|Average Household Income||$65,454|
|Per Capita Income||$27,247|
|Total Housing Units||1,407 (100%)|
|Owner Occupied HU||893 (63.5%)|
|Renter Occupied HU||387 (27.5%)|
|Vacant Housing Units||127 ( 9.0%)|
|Median Home Value||$150,758|
|Average Home Value||$161,897|
|Average Household Size||2.34|
|Average Family Size||3|
GROWTH RATE / YEAR
|Median Household Income||2.44%|
|Per Capita Income||3.25%|
The table below compares Jefferson to the other 1,215 incorporated cities, towns and CDPs in Ohio by rank and percentile using July 1, 2018 data. The location Ranked # 1 has the highest value. A location that ranks higher than 75% of its peers would be in the 75th percentile of the peer group.
|Total Population||# 398||67th|
|Population Density||# 614||50th|
|Diversity Index||# 767||37th|
|Median Household Income||# 458||62nd|
|Per Capita Income||# 477||61st|
Additional comparisons and rankings can be made with a VERY EASY TO USE Ohio Census Data Comparison Tool.